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tanszek:oktatas:techcomm:shanon-fano_method

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tanszek:oktatas:techcomm:shanon-fano_method [2024/10/08 08:39] kneheztanszek:oktatas:techcomm:shanon-fano_method [2024/10/08 08:45] (current) knehez
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 After substituting: After substituting:
  
-$$ L = \frac{2}{4} \dot 2 + \frac{2}{8} \dot 3  + \frac{4}{16} \dot 4 = 2.75 [bit]$$+$$ L = \frac{2}{4} \cdot 2 + \frac{2}{8} \cdot 3  + \frac{4}{16} \cdot 4 = 2.75 \,\text{ [bit]}$$
  
-The original 8 symbols (X1-X8) can be stored with 4 bits. The average length is 2.75 bits, thus the compressed messages will be  \(\frac{2.75}{4} \arrow 68.75% \) shorter.+The original 8 symbols (X1-X8) can be stored with 4 bits. The average length is 2.75 bits, thus the compressed messages will be  \(\frac{2.75}{4} \approx 68.75\% \) shorter.
  
tanszek/oktatas/techcomm/shanon-fano_method.1728376799.txt.gz · Last modified: 2024/10/08 08:39 by knehez